When defining a macro you must pay attention to the number of times the arguments will be evaluated when the expansion is executed. The following macro (used to facilitate iteration) illustrates the problem. This macro allows us to write a for-loop construct.
(defmacro for (var from init to final do &rest body) "Execute a simple \"for\" loop. For example, (for i from 1 to 10 do (print i))." (list 'let (list (list var init)) (cons 'while (cons (list '<= var final) (append body (list (list 'inc var)))))))
(for i from 1 to 3 do (setq square (* i i)) (princ (format "\n%d %d" i square))) →
(let ((i 1)) (while (<= i 3) (setq square (* i i)) (princ (format "\n%d %d" i square)) (inc i)))
-|1 1 -|2 4 -|3 9 ⇒ nil
The arguments from
, to
, and do
in this macro are
syntactic sugar; they are entirely ignored. The idea is that you
will write noise words (such as from
, to
, and do
)
in those positions in the macro call.
Here’s an equivalent definition simplified through use of backquote:
(defmacro for (var from init to final do &rest body) "Execute a simple \"for\" loop. For example, (for i from 1 to 10 do (print i))." `(let ((,var ,init)) (while (<= ,var ,final) ,@body (inc ,var))))
Both forms of this definition (with backquote and without) suffer from
the defect that final is evaluated on every iteration. If
final is a constant, this is not a problem. If it is a more
complex form, say (long-complex-calculation x)
, this can slow
down the execution significantly. If final has side effects,
executing it more than once is probably incorrect.
A well-designed macro definition takes steps to avoid this problem by
producing an expansion that evaluates the argument expressions exactly
once unless repeated evaluation is part of the intended purpose of the
macro. Here is a correct expansion for the for
macro:
(let ((i 1) (max 3)) (while (<= i max) (setq square (* i i)) (princ (format "%d %d" i square)) (inc i)))
Here is a macro definition that creates this expansion:
(defmacro for (var from init to final do &rest body) "Execute a simple for loop: (for i from 1 to 10 do (print i))." `(let ((,var ,init) (max ,final)) (while (<= ,var max) ,@body (inc ,var))))
Unfortunately, this fix introduces another problem, described in the following section.